Answer:
Explanation:
In terms of volume of water per unit time , the speed of water flow =
115 / 15.6 cm³ / s
= 7.37 cm³ / s
radius of faucet = .42 cm
cress sectional area
A = π x .42²
= .5539 cm²
a )
If speed of flow at the time of coming out be v
v x A = volume rate of flow
v x .5539 = 7.37
v = 13.3 cm /s
b )
pressure = atmospheric pressure will work at that point .
c )
Applying Bernoulli's theorem for points at the opening of faucet and a point 24 cm below .
P + 1/2 ρv² + ρ gh = constant
P + 1/2 ρv₁² + ρ gh₁ = P + 1/2 ρv₂² + ρ gh₂
1/2 ρ (v₂² - v₁² ) = ρ g(h₁-h₂ )
.5 x 1 ( v₂² - 13.3² ) = 1 x 981 x 24
v₂² - 13.3² = 47088
v₂² = 47264.89
v₂ = 217.4 cm /s
= 2.17 m /s
