Answer:
x = 8 units.
Step-by-step explanation:
I think your question is missed of key information, allow me to add in and hope it will fit the original one.
The areas of the squares adjacent to two sides of a right triangle are 32 unit square and 32 units square. Find the length,x, of the third side of the triangle
My answer:
The area of the 1st square is equal to 32 units square
<=> [tex]a^{2} = 32[/tex]
<=> a = [tex]4\sqrt{2}[/tex] units
The area of the 2nd square is equal to 32 units square
<=> [tex]b^{2}[/tex] = 32
<=> b = [tex]4\sqrt{2}[/tex] units
Applying the Pythagoras Theorem, we have:
[tex]x^{2} = a^{2} + b^{2}[/tex]
<=> [tex]x^{2} = 32 + 32[/tex]
<=> [tex]x^{2} = 64[/tex]
<=> x = 8 units
Hope it will find you well.
