Answer:
The concentration of KBr is [tex]C = 0.07899 \ mol L^{-1}[/tex]
Explanation:
From the question we are told that
The mass of KBr is [tex]m_{KBr} = 2.35 \ g[/tex]
The molar mass of KBr is [tex]M_{KBr} = 119 g/mol[/tex]
Volume of water is [tex]V = 250 \ mL = 250 *10^{-3} = 0.250 \ L[/tex]
This implies that the volume of the solution is [tex]V = 250 mL[/tex]
The number of moles of KBr is
[tex]n = \frac{m_{KBr}}{M_{KBr}}[/tex]
Substituting values
[tex]n = \frac{2.35}{119}[/tex]
[tex]n = 0.01975 \ mol[/tex]
The concentration of KBr is mathematically represented as
[tex]C = \frac{0.01975}{0.250}[/tex]
[tex]C = 0.07899 \ mol L^{-1}[/tex]
