Answer:
[tex]5x^{6}y^{2} \sqrt{7xy}[/tex]
Step-by-step explanation:
Fistly , you have to know these :
[tex]a\sqrt{x} + b\sqrt{x} = (a+b)\sqrt{x} \\\sqrt{a.b^{2} } =b\sqrt{a} \\ c\sqrt{a.b^{2} } =(c.b)\sqrt{a} \\a\sqrt{x} - b\sqrt{x} = (a-b)\sqrt{x}[/tex]
About your question:
[tex]x^{3}\sqrt{175x^{7}y^{5}}[/tex]
[tex]x^{3}\sqrt{175x^{2}.x^{2}.x^{2}.x.y^{2}.y^{2}.y}[/tex]
[tex]\sqrt{175} =\sqrt{25.7} = 5\sqrt{7}[/tex]
[tex]5x^{3}\sqrt{7.x^{2}.x^{2}.x^{2}.x.y^{2}.y^{2}.y}[/tex]
[tex]5x^{3}.x.x.x\sqrt{7.x.y^{2}.y^{2}.y}[/tex]
[tex]5x^{6}\sqrt{7.x.y^{2}.y^{2}.y}[/tex]
[tex]5x^{6}.y.y\sqrt{7.x.y}[/tex]
[tex]5x^{6}.y^{2}\sqrt{7.x.y}[/tex]
=> [tex]5x^{6}y^{2} \sqrt{7xy}[/tex]<=
Hope it helps ^-^
