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1000 g of water (specific heat = 4.184 J/(g *C)) is heated from freezing (0°C) to boiling (100°C). How much heat energy is required to
achieve this temperature change? ( gotta show work too)

Respuesta :

Answer: The heat energy required to achieve this temperature change is 418400 Joules

Explanation:

The quantity of heat required to raise the temperature of a substance by one degree Celsius is called the specific heat capacity.

[tex]Q=m\times c\times \Delta T[/tex]

Q = Heat absorbed= ?

m= mass of water = 1000 g

c = specific heat capacity = [tex]4.184J/g^0C[/tex]

Initial temperature of the water = [tex]T_i[/tex] = 0°C

Final temperature of the water = [tex]T_f[/tex]  = 100°C

Change in temperature ,[tex]\Delta T=T_f-T_i=(100-0)^0C=100^0C[/tex]

Putting in the values, we get:

[tex]Q=1000g\times 4.184J/g^0C\times 100^0C[/tex]

[tex]Q=418400J[/tex]

The heat energy required to achieve this temperature change is 418400 Joules