On a coordinate plane, a parallelogram has points A (negative 3, 4), B (3, 4), C (1, negative 2), and D (negative 5, negative 2). If a translation of (x, y) → (x + 6, y – 10) is applied to figure ABCD, what are the coordinates of D'? (–5, –2) (1, –12) (4, –15) (–9, –6)

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gcschilling20 gcschilling20 · Answer 1 · 2020-06-10T22:33:41+02:00

Answer:

(1,-12)

Step-by-step explanation:

d starts at (-5,-2) if you add 6 to -5 and minus -2 by 10 you will end up with (1,-12)

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jainveenamrata jainveenamrata · Answer 2 · 2022-08-03T08:36:28+02:00

The coordinate of the point D' will be at (1, –12). Then the correct option is B.

A spatial transformation is each mapping of feature shapes to itself, and it maintains some spatial correlation between figures.

Translation does not change the size and shape of the geometry. But change the location of the shape.

On a coordinate plane, a parallelogram has points A (-3, 4), B (3, 4), C (1, -2), and D (-5, -2).

If a translation of (x, y) → (x + 6, y – 10) is applied to figure ABCD.

Then the coordinate of the A', B', C', AND D' will be

A' ⇒ (–3 + 6, 4 – 10) = (3, –6)

B' ⇒ (3 + 6, 4 – 10) = (9, –6)

C' ⇒ (1 + 6, –2 – 10) = (7, –12)

D' ⇒ (–5 + 6, –2 – 10) = (1, –12)

Then the coordinate of the point D' will be at (1, –12).

Then the correct option is B.

The diagram is given below.

More about the transformation of geometry link is given below.

https://brainly.com/question/22532832

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