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What is the solution to the system of equations below?

2 x minus y = 10 and y = negative one-half x + 5
(6, 2)
(6, –2)
(–6, –22)
(–6, 8)

Respuesta :

markoskontoulis

Answer:

The correct one is A

Step-by-step explanation:

2x-y=10

y=1/2 × x+5

Now you substitute the value of y into the first equation.

2x - (1/2 × x+5) = 10

Solving this equation for x you get that x=6

Now substitute the value of x any of these two equations, doesn't matter. Let's say we do with the first one.

2×6-y=10

12-y=10

-y=10-12

-y= -2

y=2

And so you've got the first one which is, (x,y)=(6,2)

The solution to the system of equations below will be,(x,y) will be (6, 2). Option A is correct.

What is the system of two equations?

A set of two linear equations with two variables is called a system of linear equations. They create a system of linear equations when evaluated collectively.

The given equation in the problem is;

Equation 1: 2x-y=10

Equation 2: y=1/2 × x+5

From equation 1 value of y is ;

y =2 x -10

Now you substitute the value of y into the first equation.

⇒y =2 x -10

⇒y=1/2 × x+5

⇒2x - 10 =  ((1/2)x+5)

⇒2x-10 = 0.5 x +5

The value of x will be 6

⇒2x-y=10

⇒12-y=10

⇒-y=10-12

⇒-y= -2

⇒y=2

The solution to the system of equations below will be, (x,y)=(6,2)

To learn more about the system of two equations, refer to the link;

https://brainly.com/question/21620502

#SPJ2

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