Simon can see two lights, light A and light B.

Light A flashes every 15 seconds.
Light B flashes every 18 seconds.

At 10 pm, both lights flash at the same time.

How many more times will both lights flash at the same time in the next 4 minutes?

Respuesta :

Answer:

2 Times

Step-by-step explanation:

Light A flashes every 15 seconds.

Light B flashes every 18 seconds.

First, we determine the next time both lights will flash together.

This is done by finding the Least Common Multiple of the two numbers.

15=3X5

18=[tex]2X3^2[/tex]

LCM of 15 and 18=[tex]2X3^2X5=90[/tex]

This means that both lights will flash together after 90 seconds.

Now, 4 Minutes =4 X 60 =240

240=90+90+60

Therefore, the number of times more both light will flash together in the next 4 Minutes

= 2 Times

Using the least common multiple, it is found that in the next 4 minutes, they will flash together 2 more times.

To find the time that passes between them flashing at the same time, we need to find the least common multiple of 15 and 18, hence:

15 - 18|2

15 - 9|3

5 - 3|3

5 - 1|5

1

Hence, lcm(15, 18) = 2 x 3 x 3 x 5 = 90 seconds.

In 4 minutes, there are 240 seconds.

240/90 = 2.67

In the next 4 minutes, they will flash together 2 more times.

A similar problem is given at https://brainly.com/question/20726647