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What is the critical angle for glass which has a refractive index of n=1.6?

Respuesta :

Chelboy

Answer:38.7

Explanation:

Refractive index=n=1.6

Critical angle=c

n=1/sinc

1.6=1/sinc

Cross multiply

1.6xsinc=1

Divide both sides by 1.6

(1.6xsinc)/1.6=1/1.6

sinc=1/1.6

sinc=0.625

c=sin(inverse)(0.625)

c=38.7

Critical angle is 38.7°

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