Answer:
11 + [tex]\sqrt{65}[/tex]
Step-by-step explanation:
The base of the triangle = 7 units ( count squares )
The right side = 4 units
Since the triangle is right, use Pythagoras' identity to find AB
The square on the hypotenuse (AB) is equal to the sum of the squares on the other 2 sides, that is
AB² = 7² + 4² = 49 + 16 = 65 ( take the square root of both sides )
AB = [tex]\sqrt{65}[/tex], thus
Perimeter = 7 + 4 + [tex]\sqrt{65}[/tex] = 11 + [tex]\sqrt{65}[/tex]
