Respuesta :
0.668 moles!
1 mole of Fe weighs 55.845 g.
1 mole has 6.02*10^23 atoms.
(4.02*10^23)/(6.02/10^23) = 4.02/6.02=2.01/3.01=0.668 moles
1 mole of Fe weighs 55.845 g.
1 mole has 6.02*10^23 atoms.
(4.02*10^23)/(6.02/10^23) = 4.02/6.02=2.01/3.01=0.668 moles
The number of moles of iron in which 4.02×10²³ atoms are present is 0.66 mole.
What is Avogadro's number?
Avogadro's number is the number of atoms which are present in 1 mole of any substance and it is equal to 6.022×10²³.
i.e. 1 mole = 6.022×10²³ atoms/ mole
Given atoms of iron = 4.02×10²³ atoms
Moles of iron will be calculated as:
Moles of Fe = 4.02×10²³ atoms / 6.022×10²³ atoms/mole
Moles = 0.66 moles
Hence required moles of iron is 0.66 moles.
To know more about Avogadro's number. visit the below link:
https://brainly.com/question/1513182
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