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PLEASE HELPPPPPPP
a 8.02 gram sample of gas was found to have a volume of 812 mL when measured under the pressure of 0.967 atm at 30.0 celsius . calculate its molecular weight

Respuesta :

Answer:

Molar mass = 254.60g/mol

Step-by-step explanation:

Mass = 8.02g

Volume = 812mL = 0.812L

Pressure (P) = 0.967atm

Temperature of the gas = 30°C = (30 + 273.15)K = 303.15K

Molecular weight = ?

To solve this question, we'll have to use ideal gas equation, PV = nRT

P = pressure of the gas

V = volume of the gas

n = number of moles of the gas

R = ideal gas constant = 0.082J/mol.K

T = temperature of the gas

PV = nRT

n = PV / RT

n = (0.967 * 0.812) / (0.082 * 303.15)

n = 0.7852 / 24.8583

n = 0.0315 moles

Number of moles = mass / molarmass

Molarmass = mass / number of moles

Molar mass = 8.02 / 0.0315

Molar mass = 254.60g/mol

The molar mass of the gas is 254.60g/mol