Answer: B
F = 2.4 N
Explanation: Given that
Magnetic field B = 0.60 T
Current I = 5 A
Length L = 0.8 m
The force on an individual charge moving at the drift velocity Vd is given by F = qVdB sin θ.
Since current = charge/time
I = q/t
q = It
Also, recall that V = L/t. Therefore
F = I × t × L/t × B × sinØ
F = ILBsin θ
Since the wire is at right angles to the magnetic field
Sin θ = sin 90 = 1 then,
F = 5 × 0.8 × 0.6 = 2.4N
The force on the wire is 2.4 N
