Three letters are chosen at random from the letters P, A, N, S, O, L. What is the size of the sample space of this experiment? Assume that the order of the letters matters. That is, PAN is different from APN
You need to find the number of permutations of the 6 different letters, taken 3 at a time. [tex]6P3=\frac{6!}{(6-3)!}=\frac{6\times5\times4\times3\times2\times1}{3\times2\times1}=120[/tex] Therefore the sample space is 120 possible outcomes.
