Respuesta :
As it is required for 25 adults and 6 children.
Putting the value of a with 25 and c with 5, then solve for m.
m = 4(25) + 2(5)
m = 100 + 10
m = 110 meatballs are required.
Putting the value of a with 25 and c with 5, then solve for m.
m = 4(25) + 2(5)
m = 100 + 10
m = 110 meatballs are required.
Answer:
112 meat balls are required for a party of 25 adults and 6 children.
Step-by-step explanation:
As per the statement:
Frank has devised a formula for his catering business that calculates the number of meatballs he needs to prepare.
The formula is given by:
[tex]m = 4a+2c[/tex]
where;
c= number of children;
m= number of meatballs;
a= number of adults.
We have to find how many meat balls are required for a party of 25 adults and 6 children.
⇒a = 25 and c = 6
then;
[tex]m = 4(25)+2(6) = 100+12 = 112[/tex]
Therefore, 112 meat balls are required for a party of 25 adults and 6 children.