Answer:
[tex]\frac{f(x)}{g(x)}=\frac{2(4x^3-11x^2-2)}{4x-3}[/tex]
Step-by-step explanation:
The given functions are.....
[tex]f(x)= 8x^3-22x^2-4\\ \\ g(x)=4x-3[/tex]
Using the above functions, we will get......
[tex]\frac{f(x)}{g(x)}\\ \\ =\frac{8x^3-22x^2-4}{4x-3}\\ \\ =\frac{2(\frac{8x^3}{2}-\frac{22x^2}{2}-\frac{4}{2})}{4x-3}\\ \\ =\frac{2(4x^3-11x^2-2)}{4x-3}[/tex]
