The induced current in the loop is 20 A
Further explanation
Lenz's law said that when EMF is generated by the change in magnetic flux the polarity of the induced EMF produces an induced current. It induced electric current flows in a direction such that the current opposes the change that induced it
The square loop shown in the figure moves into a 0.80T magnetic field at a constant speed of 10m/s. The loop has a resistance of 0.10Ω, and it enters the field at t = 0s. Find the induced current in the loop as a function of time. Give your answer as a graph of I versus t from t = 0s to t = 0.020s.
B = 0.8 T
L = 5 cm
v = 10 m/s
R = 0.10 Ω
I = ?
∈=E
Ф=o
[tex]I = \frac{E }{R} = \frac{1}{R} |\frac{d o_{m}}{dt} | = \frac{1}{R} \frac{d}{dt} |B.dA|\\I = \frac{1}{R} \frac{d}{dt} |B.dl\Delta s|\\I = \frac{B*l}{R} \frac{ds}{dt} \\I = \frac{B*lv}{R} = \frac{0.80 T*0.05m*50m/s}{0.10 ohm}[/tex]
[tex]I = \frac{B*lv}{R} = 20A[/tex]
The induced current in the loop is 20 A. According to Lenz's law I goes to counterwise
Learn more
- Learn more about magnetic field https://brainly.com/question/9969693
- Learn more about constant speed https://brainly.com/question/12427728
-
Learn more
about the induced current https://brainly.com/question/3712635
Answer details
Grade: 8
Subject: physics
Chapter: Lenz's law
Keywords: magnetic field, constant speed, the induced current, loop, resistance
