Sketch one cycle of the cosine function. y = 2 cos 2 theta

So the question ask to sketch the one cycle of the cosine function where as the y = 2cos theta. So base on the function, its just and ordinary graph but the data is not the same. The line begins at the positive 2 in the Y axis then goes down with constant magnitude after it reach its limit it goes up again with constant magnitude and its limit in negative y axis is -2.

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tardymanchester tardymanchester · Answer 2 · 2019-05-07T10:14:43+02:00

Answer:

One cycle is of period π.

Step-by-step explanation:

Given : Cosine function [tex]y=2\cos 2\theta[/tex]

To find : Sketch one cycle of the cosine function ?

Solution :

The general form of cosine function is [tex]y=a \cos (bx-c)+d[/tex]

On comparing with [tex]y=2\cos 2\theta[/tex]

a=2 , b=2 , c=0, d=0

Where, Amplitude is [tex]|a|=|2|[/tex]

Amplitude = 2

[tex]\text{Period}=\frac{2\pi}{|B|}[/tex]

[tex]\text{Period}=\frac{2\pi}{|2|}[/tex]

[tex]\text{Period}=\pi[/tex]

Phase shift and vertical shift is zero.

Therefore, One cycle is of period π.

Refer the attached figure below.