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in competition, an athlete threw a flying disk 139 meters through the air. while in flight, the disk traveled at an average speed of 13.0 m/s. how long did the disk remain in the air?

Respuesta :

Misf2
139m/13.0m/s = 10.7sec
aachen

Answer:

Time, t = 10.69 seconds

Explanation:

Given that,

Average speed of the disk, v = 13 m/s

The athlete threw a distance through the air, d = 139 meters

We need to find the time the disk remains in the air. Let t is the time taken. The average speed of the disk is given by :

[tex]v=\dfrac{d}{t}[/tex]

[tex]t=\dfrac{d}{v}[/tex]

[tex]t=\dfrac{139\ m}{13\ m/s}[/tex]

t = 10.69 seconds

So, the disk remains in the air for 10.69 seconds. Hence, this is the required solution.

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