Answer:
[tex]x\geq\frac{40}{13}[/tex]
Step-by-step explanation:
We have been given an inequality which is:
8 less than 13 times a number x which gives 8-13 x
And less than or equal to -32 which gives: [tex]8-13x\leq -32[/tex]
We will solve for x we get:
[tex]-13x\leq -32-8[/tex]
[tex]-13x\leq -40[/tex]
On further simplification we get:
[tex]x\geq\frac{40}{13}[/tex]
