Answer : The volume of 3.0 M spinach solution added should be, 50 mL
Explanation :
Formula used :
[tex]M_1V_1=M_2V_2[/tex]
where,
[tex]M_1\text{ and }V_1[/tex] are the initial molarity and volume of spinach solution.
[tex]M_2\text{ and }V_2[/tex] are the final molarity and volume of diluted spinach solution.
We are given:
[tex]M_1=3.0M\\V_1=?\\M_2=0.30M\\V_2=500.0mL[/tex]
Now put all the given values in above equation, we get:
[tex]3.0M\times V_1=0.30M\times 500.0mL\\\\V_1=50mL[/tex]
Hence, the volume of 3.0 M spinach solution added should be, 50 mL
