Answer:
Just 0.335 of the light is transmitted through the second polarizer
Explanation:
When the light passes through to the second polarizer, the intensity is equal:
[tex]I_{2}= \frac{I}{2} cos\theta[/tex]
Where
θ = 48°
Replacing:
[tex]I_{2}= \frac{I}{2} cos\48=0.335I[/tex]
