Calculate the change in entropy that occurs in the system when 1.24 mol of isopropyl alcohol (c3h8o) melts at its melting point (-89.5 ∘c). heat of fusion is 5.37 kj/mol.

Respuesta :

Answer: The change in entropy that occurs in the system is 36.3 J/Kmol

Explanation:

Given : 1 mole of isopropyl alcohol gives heat = 5.37 kJ

Thus 1.24 moles of isopropyl alcohol gives heat = [tex]\frac{5.37}{1}\times 1.24=6.66 kJ[/tex]

To calculate the temperature , we use the equation:

[tex]\Delta S_f=\frac{\Delta H_{f}}{T}[/tex]  

where,  

[tex]\Delta S_f[/tex] = Entropy of fusion = ?

[tex]\Delta H_{f}[/tex] = enthalpy of fusion  = 6.66 kJ/mol = 6660 J/mol     (1kJ=1000J)

T = melting point = [tex]-89.5^0C=(273-89.5)K=183.5K[/tex]

[tex]\Delta S_f=\frac{6660J/mol}{183.5K}=36.3J/Kmol[/tex]

Thus the change in entropy that occurs in the system is 36.3 J/Kmol