Suppose that the price p, in dollars, and number of sales, x, of a certain item follow the equation 5p+4x+2px=60. Suppose also that p and x are both functions of time, measured in days. Find the rate at which x is changing when x=3, p=5, and dpdt=1.5.\

Respuesta :

Answer:

[tex]\frac{dx}{dt}=-\frac{33}{28} =-1.1786[/tex]

Step-by-step explanation:

Given that the price p, in dollars, and number of sales, x, of a certain item follow the equation:

5p+4x+2px=60.

Taking partial derivatives

[tex]5\frac{dp}{dt} +4\frac{dx}{dt}+2x\frac{dp}{dt}+2p\frac{dx}{dt}=0\\(4+2p)\frac{dx}{dt}=(-5-2x)\frac{dp}{dt}\\\frac{dx}{dt}=\frac{-5-2x}{4+2p} \cdot \frac{dp}{dt}[/tex]

When x=3, p=5, dp/dt=1.5

[tex]\frac{dx}{dt}=\frac{-5-2(3)}{4+2(5)} \cdot 1.5\\=\frac{-5-6}{4+10} \cdot 1.5\\=\frac{-11}{14} \cdot 1.5\\\frac{dx}{dt}=-\frac{33}{28} =-1.1786[/tex]

Therefore, x is decreasing at a rate of -1.1786.