Respuesta :
Answer:
The density of the block is 7.4g/ml.
Explanation:
We can determine the volume of the metal block by taking the difference between the volumes measured in the graduated cylinder:
[tex]V_{block}=65.5ml-62ml\\\\V_{block}=3.5ml[/tex]
Now, as we know that the average density of an object is calculated dividing its mass by its volume, we can calculate the density ρ of the metal block using the expression:
[tex]\rho_{block}=\frac{m_{block}}{V_{block}}\\\\\rho_{block}=\frac{26g}{3.5ml}\\\\\rho_{block}=7.4\frac{g}{ml}[/tex]
Finally, it means that the density of the metal block is 7.4g/ml.
Answer:
7.43 g/mL
Explanation:
Step 1:
Data obtained from the question. This include:
Volume of water = 62 mL
Volume of (Metal + water) = 65.5 mL
Mass of metal = 26g
Density =?
Step 2:
Determination of the volume of the block.
From Archimedes' principle, we understood that an object will displace its own volume when completely immersed in a liquid. The volume of the metal block can be obtained as follow:
Volume of water = 62 mL
Volume of (Metal + water) = 65.5 mL
Volume of the matal = Volume of (Metal + water) - volume of water
Volume of the matal = 65.5 - 62
Volume of the matal = 3.5 mL
Step 3:
Determination of the density of the metal block. This is illustrated below:
The density of an object is simply the mass of the object per unit volume of the object. It represented mathematically as:
Density = Mass /volume
Mass of the metal = 26g
Volume of the metal = 3.5 mL
Density =?
Density = Mass /volume
Density = 26g / 3.5mL
Density = 7.43 g/mL
