Respuesta :
Answer:
Electric field =h/3Eo
Explanation:
Because of the intrisic notation and symbol necessary for the solution please refer to the attached file
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The electric field inside the cavity is [tex]= \frac{ph}{3E_0}[/tex]
Following details are required to solve the electric field:
The spherical cavity is excised from the inside of the sphere.
The cavity has radius a4 and is centered at position h⃗, where |h⃗ |<34a.
Calculation of electric field:
The electric field inside the cavity because of the remaining portions of the sphere i.e. provided by applying the following formulas:
[tex]E '' = E - E' = \frac{p(h - \frac{a}{4} }{3E_0} - \frac{pa}{4/3E_0} = \frac{ph}{3E_0}[/tex]
Learn more about the sphere here:
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