Answer:
7.8 in
Step-by-step explanation:
Given:-
- The dimension of rectangular prism:
(3 x 4 x 6) inches
Find:-
What is the length of the diagonal from the point R to point S, to the nearest tenth of an inch?
Solution:-
- We will set up an origin with coordinates ( 0 , 0 , 0 ) at point R. Then the coordinates of point S would be ( 3 , 4 , 6 ).
- Then we will use the distance between two points formula in cartesian coordinate system:
Distance = [tex]\sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2 + (z_1 - z_2)^2}[/tex]
Where the coordinates of two points ( x1 , y1 , z1 ) & ( x2 , y2 , z2 ).
- Using R( 0 , 0 , 0 ) & S( 3 , 4 , 6 ), the distance |RS| would be:
[tex]|RS| = \sqrt{(0 - 3)^2 + (0 - 4)^2 + (0 - 6)^2}\\\\|RS| = \sqrt{ 9 + 16 + 36}\\\\|RS| = \sqrt{61} = 7.81024[/tex]
- The distance |RS| to nearest 10th of an inch is = 7.8 in
