A swim school is expanding and needs to take out a one-year, $55,000 loan for a new lap pool. Bank A says it can give the swim school a 25% annual interest rate compounded once. This is represented with the equation A=55,000(1.25)t. A = 55,000 ( 1.25 ) t . Bank B says it can offer the swim school a semi-annual interest rate that will be compounded twice. In order for the loan at Bank B to cost the swim school the same amount, what APR would Bank B need to offer?

Respuesta :

Answer:

Therefore the bank need to offer 23.6% annual interest rate compounded twice.

Step-by-step explanation:

Compound interest formula:

[tex]A=P(1+\frac rn)^{nt}[/tex]

A=Amount

P=Principal

r=rate of interest

n= Number of times interest is compounded per year.

t= time

Bank A

P=$55,000, r=25% = 0.25, n=1, t=t

The amount that the school have to pay after t year is

[tex]A_1=55,000(1+0.25)^t[/tex]

   [tex]=55000(1.25)^t[/tex]

Bank B

P=$55,000, r=?, n=2, t=t

The amount that the school have to pay after t year is

[tex]A_2=55,000(1+\frac r2)^{2t}[/tex]

Since the amount for both banks are same.

i.e

[tex]A_1=A_2[/tex]

[tex]\Rightarrow 55000(1.25)^t=55000(1+\frac r2)^{2t}[/tex]

[tex]\Rightarrow (1.25)^t=(1+\frac r2)^{2t}[/tex]

[tex]\Rightarrow (1.25)=(1+\frac r2)^{2}[/tex]

[tex]\Rightarrow (1+\frac r2)=\sqrt{1.25}[/tex]

[tex]\Rightarrow (1+\frac r2)=1.118[/tex]

[tex]\Rightarrow \frac r2=1.118-1[/tex]

[tex]\Rightarrow \frac r2=0.118[/tex]

⇒r=0.118×2

⇒r = 0.236

⇒r =23.6%

Therefore the bank need to offer 23.6% annual interest rate compounded twice.