Answer: The original volume in liters was 0.0707L
Explanation:
Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.
The combined gas equation is,
[tex]\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}[/tex]
where,
[tex]P_1[/tex] = initial pressure of gas = 0.85 atm
[tex]P_2[/tex] = final pressure of gas = 456 mm Hg = 0.60 atm (760mmHg=1atm)
[tex]V_1[/tex] = initial volume of gas = ?
[tex]V_2[/tex] = final volume of gas = 94.0 ml
[tex]T_1[/tex] = initial temperature of gas = [tex]66^oC=273+66=339K[/tex]
[tex]T_2[/tex] = final temperature of gas = [tex]113^oF=318K[/tex] [tex](32^0F=273K)[/tex]
Now put all the given values in the above equation, we get:
[tex]\frac{0.85\times V_1}{339}=\frac{0.60\times 94.0}{318}[/tex]
[tex]V_1=70.7ml=0.0707L[/tex] (1L=1000ml)
Thus the original volume in liters was 0.0707L
