Respuesta :
Answer:
The height is [tex]h =37.17m[/tex]
Explanation:
From the question we are told that
The concentration inside a is tree [tex]M= 0.15M[/tex]
The temperature condition is [tex]T = 19^oC = 19+ 273 = 292K[/tex]
The density of the fluid is [tex]\rho = 1.1 g/cm^3[/tex]
The density of mercury is [tex]\rho__{Hg} = 13.6 g/cm^3[/tex]
Generally osmotic pressure experience is mathematically represented as
[tex]P_o =MRT[/tex]
Where R is the universal gas constant with a value of R = 00821 L.atm/K/mol
[tex]P_o = 0.15 * 0,0821* 292[/tex]
[tex]=3.59598 atm[/tex]
Converting to cm of Mercury
[tex]P_o = 3.59598 * 76 cm of Hg[/tex]
[tex]= 273.29 \ cm \ of \ Hg[/tex]
Generally pressure is mathematically represented as
[tex]P = \frac{Height }{Density }[/tex]
Now making height the subject
[tex]Height = pressure * Density[/tex]
Where pressure is [tex]= 273.29 \ cm \ of \ Hg[/tex]
and Density is [tex]\rho__{Hg} = 13.6 g/cm^3[/tex]
So we have
[tex]Height (h) = 273.29 * 13.6[/tex]
[tex]= 3716.8 cm[/tex]
In meters h [tex]= \frac{3716.8}{100} = 37.17m[/tex]
[tex]h =37.17m[/tex]
Answer:
The fluid column will rise a height of 3720.96 cm
Explanation:
The osmotic pressure is equal:
[tex]P_{osm} =MRT[/tex]
Where
M = 0.15 M
T = 19ºC = 292 K
Replacing:
[tex]P_{osm} =0.15*0.0821*292=3.6atm=273.6cmHg[/tex]
The height is:
[tex]h=P_{osm} \rho[/tex]
Where
ρ = 13.6 g/cm³
Replacing:
[tex]h=273.6*13.6=3720.96cm[/tex]
