Answer:
θ₂ = 90° - θ₁
Explanation:
When the light falls on a mirror it bounces back. This is know as reflection. The incident angle is equal to the angle of reflection.
Here, the light strikes the mirror at an angle = θ₁
To find the angle of reflection we first need to understand angle of incidence. The angle of incidence is the angle made between the incident ray and normal. Normal is an imaginary line drawn perpendicular line on the boundary of the mirror.
Since the light strikes the mirror at angle of θ₁, which is the angle between light ray and the mirror.
Angle of incidence = 90° - θ₁.
Thus, angle of reflection, θ₂ = 90° - θ₁
The required value of the reflected angle is θ₂ = 90° - θ₁.
The given problem is based on the phenomena of reflection of light. The bouncing back of light rays from the surface is known as reflection.
[tex]\theta_{2}=90^{\circ}- \theta_{1}[/tex]
Thus, we can conclude that the reflected angle is θ₂ = 90° - θ₁.
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