The base of a triangular prism is an isosceles right triangle with a hypotenuse of 72−−√ centimeters. The height of the prism is 7 centimeters. Find the surface area of the triangular prism. Round your answer to the nearest tenth.

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Answer:

Step-by-step explanation:

Surface area = lateral area + 2(area of base)

Lateral area = perimeter of base * height.

Because it is a isosceles right triangle, both sides are equal.

[tex]x^{2} +x^{2}[/tex] = 72

2[tex]x^{2}[/tex] = 72. Divide both sides by 2

[tex]x^{2}[/tex] = 36.  Square both sides.

x = 6.

So the perimeter of the base = 6 + 6 +[tex]\sqrt{72}[/tex] = 20.485281374239

Lateral area = 20.485281374239 * 7 = 143.397 [tex]cm^{2}[/tex]

Area of base is (1/2)base * height.

(1/2)(6)(6) = 18

Using the surface area formula

surface area = 143.397 + 2(18) = 179.4 [tex]cm^{3}[/tex]