A resistor, an inductor, and a switch are all connected in series to an ideal battery of constant terminal voltage. Suppose at first the switch is open, and then, at some initial time t = 0, it is closed. Which of the following statements are true? Check all that apply. Check all that apply.a.At the instant the switch is closed, the current reaches its steady-state value. b.At the instant the switch is closed, the current begins to increase at a rate that depends upon the value of the inductance of the inductor. c.The steady-state value of the current depends on the resistance of the resistor. d.The steady-state value of the current depends on the inductance of the inductor.

Since all the components are connected in series, when the switch is at first open, current will not flow round the circuit. As current needs to flow through from the positive terminal of the battery through the resistor, inductor, and switch to the negative terminal of the battery.

But the moment the switch is closed, at the initial time t = 0, the current flow through from the positive terminal of the battery through the resistor, inductor, and switch to the negative terminal of the battery. It then begins to increase at a rate that depends upon the value of the inductance of the inductor.

onyebuchinnaji onyebuchinnaji · Answer 2 · 2021-11-17T09:36:06+01:00

The steady-state value of the current depends on the resistance of the resistor.

The overall opposition to the flow of current due to the combination of resistor and inductor is given as;

[tex]Z = \sqrt{X_l^2 + R^2}[/tex]

For a given value of voltage in the circuit, the alternating current (AC) is calculated as;

[tex]I_{AC} = \frac{V}{Z} = \frac{V}{\sqrt{X_l^2 + R^2} }[/tex]

The steady state current (direct current) in the circuit is calculated as;

[tex]I_{DC} = \frac{V}{R}[/tex]

Thus, we can conclude that the steady-state value of the current depends on the resistance of the resistor.

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