Answer : The volume of solution will be, 0.309 L
Explanation : Given,
Mass of [tex](NH_4)_2SO_4[/tex] = 449.4 g
Molar mass of [tex](NH_4)_2SO_4[/tex] = 132 g/mole
Concentration = 11 M
Molarity : It is defined as the number of moles of solute present in one liter of volume of solution.
Formula used :
[tex]\text{Molarity}=\frac{\text{Mass of }(NH_4)_2SO_4}{\text{Molar mass of }(NH_4)_2SO_4\times \text{Volume of solution (in L)}}[/tex]
Now put all the given values in this formula, we get:
[tex]114M=\frac{449.4g}{132g/mole\times \text{Volume of solution (in L)}}[/tex]
[tex]\text{Volume of solution (in L)}=0.309L[/tex]
Therefore, the volume of solution will be, 0.309 L
