Answer:
10 turns
Explanation:
From Transformer equation,
Ns/Np = Vs/Vp................... Equation 1
Where Np = Number of turns in the secondary coil, Np = Number of turns in the primary coil, Vs = Voltage in the secondary coil, Vp = Voltage in the primary coil.
make Ns the subject of the equation
Ns = (Vs/Vp)Np.................. Equation 2
Given: Vs = 335.7 mV = 0.3357 V, Vp = 120 V, Np = 3575
Substitute into equation 2
Ns = (0.3357/120)3575
Ns = 10 turns
Ns = 10 turns
Thus the number of turns in the secondary coil = 10 turns
Answer:
10 turns
Explanation:
Parameters given:
Input voltage, [tex]V_{in}[/tex] (voltage at the primary coil) = 120 V
Output voltage, [tex]V_{out}[/tex] (voltage at the secondary coil) = 335.7 mV = 0.3357 V
Number of turns in primary coil, [tex]N_p[/tex] = 3575
The ratio relating the turns in the primary and secondary coil in of a transformer and the number of turns in each coil is given as:
[tex]\frac{V_{out}}{V_{in}} = \frac{N_s}{N_p}[/tex]
where [tex]N_s[/tex] = Number of turns in secondary coil
Therefore:
[tex]N_s = \frac{N_p * V_{out}}{V_{in}}[/tex]
[tex]N_s = \frac{3575 * 0.3357}{120}[/tex]
[tex]N_s = 10.001[/tex] ≅ 10 turns
There are 10 turns in the secondary coil of the adapter.
