Answer : The velocity of hydrogen at the same temperature is, 2116.6 m/s
Explanation :
According to the Graham's law, the rate of effusion of gas is inversely proportional to the square root of the molar mass of gas.
[tex]R\propto \sqrt{\frac{1}{M}}[/tex]
In terms of velocity,
[tex]\frac{V_1}{V_2}=\sqrt{\frac{M_2}{M_1}}[/tex]
where,
[tex]V_1[/tex] = velocity of nitrogen = 800 m/s
[tex]V_2[/tex] = velocity of hydrogen = 800 m/s
[tex]M_1[/tex] = Molar mass of nitrogen = 14 g/mol
[tex]M_2[/tex] = Molar mass of hydrogen = 2 g/mol
Now put all the given values in the above expression, we get:
[tex]\frac{800m/s}{V_2}=\sqrt{\frac{2}{14}}[/tex]
[tex]V_2=2116.6m/s[/tex]
Therefore, the velocity of hydrogen at the same temperature is, 2116.6 m/s