A flexible container at an initial volume of 5.120 L contains 8.500 mol of gas.
More gas is then added to the container until it reaches a final volume of 18.10
L. Assuming the pressure and temperature of the gas remain constant,
calculate the total number of moles of gas in the container.

Respuesta :

Answer:

30.05 mol

Explanation:

solving the proportion

V1 / n1 = V2 / n2

5.120 L            18.10 L

–––––––– = ––––––

8.500 mol         x

x = 30.05 mol

The final number of moles in the container is required.

The final amount of moles is 30.05 moles.

[tex]V_1[/tex] = Initial volume = 5.12 L

[tex]n_1[/tex] = Initial moles = 8.5 mol

[tex]V_2[/tex] = Final volume = 18.1 L

[tex]n_2[/tex] = Final moles

It is given that pressure and temperature are constant so from the ideal gas law we get

[tex]V\propto n[/tex]

So,

[tex]\dfrac{V_2}{V_1}=\dfrac{n_2}{n_1}\\\Rightarrow n_2=\dfrac{V_2}{V_1}\times n_1\\\Rightarrow n_2=\dfrac{18.1}{5.12}\times 8.5\\\Rightarrow  n_2=30.05\ \text{moles}[/tex]

The final amount of moles is 30.05 moles.

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