It is required to make 14 grams of certain chemical compound called Z. This is made from compounds W, X, and Y in the ratio of 2:1:3. The compound Y is itself made from W and X. To make 6 grams of Y requires 4 grams of W and 2 grams of X. How much W and X is required to make the required amount of Z?

W = __ grams
X = __ grams

Respuesta :

Answer:

W = 9.33 grams

X = 4.67 grams

Step-by-step explanation:

Given;

Mass of Z to be made = 14 grams

Composition of Z

W:X:Y = 2:1:3

To make 6 grams of Y requires 4 grams of W and 2 grams of X

Composition of Y (for 6grams)

W:X = 4:2 = 2:1

Substituting the composition of Y to Z

Z = W:X:Y = 2:1:3

Z = W:X:W:X = 2:1:2:1

summing them up, we have;

Z = W:X = 4:2 = 2:1

Since the final mixing ratio for W and X are 2:1, to make 14 grams of Z, we need;

W = 2/3 × 14grams = 28/3 grams

W = 9.33 grams

X = 1/3 × 14grams = 14/3 grams

X = 4.67 grams

9.32 grams of W and 4.66 grams of X are required.

Since it is required to make 14 grams of certain chemical compound called Z, and this is made from compounds W, X, and Y in the ratio of 2: 1: 3, and the compound Y is itself made from W and X, and to make 6 grams of Y requires 4 grams of W and 2 grams of X, to determine how much W and X is required to make the required amount of Z the following calculation must be performed:

  • 14/6 = 2.33
  • 4.66: 2.33: 6:99
  • 6 = 4
  • 6.99 = X
  • 6.99 x 4/6 = 4.66
  • Y = 4.66 grams of W and 2.33 grams of X
  • 4.66 x 2 = 9.32
  • 2.33 x 2 = 4.66

Therefore, 9.32 grams of W and 4.66 grams of X are required.

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