Answer: Thus [tex]0.31\times 10^3kJ[/tex] of energy is produced
Explanation:
To calculate the moles :
[tex]\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}[/tex]
[tex]\text{Moles of} C_2H_6=\frac{6.74g}{30g/mol}=0.22moles[/tex]
[tex]2C_2H_6(g)+7O_2(g)\rightarrow 4CO_2(g)+6H_2O(g)[/tex] [tex]\Delta H=-2.86\times 10^3kJ[/tex]
According to stoichiometry
2 moles of ethane produce energy = [tex]2.86\times 10^3kJ[/tex]
Thus 0.22moles of ethane produce energy =[tex]\frac{2.86\times 10^3kJ}{2}\times 0.22=0.31\times 10^3kJ[/tex]
Thus [tex]0.31\times 10^3kJ[/tex] of energy is produced
