Answer: [tex]2460J/g^0C[/tex]
Explanation:
The quantity of heat required to raise the temperature of a substance by one degree Celsius is called the specific heat capacity.
[tex]Q=C\times \Delta T[/tex]
Q = Heat absorbed by calorimeter =[tex]5682[/tex] Joules
C = heat capacity of calorimeter = ?
Initial temperature of the calorimeter = [tex]T_i[/tex] = 22.37°C
Final temperature of the calorimeter = [tex]T_f[/tex] = 24.68°C
Change in temperature ,[tex]\Delta T=T_f-T_i=(24.68-22.37)^0C=2.31^0C[/tex]
Putting in the values, we get:
[tex]5682=C\times 2.31^0C[/tex]
[tex]C=2460J/g^0C[/tex]
The heat capacity of the calorimeter is [tex]2460J/g^0C[/tex]
