Respuesta :

The new volume at standard pressure of 1 atm is 21294 liters.

Explanation:

Data given:

Initial volume of the gas V1 = 338 liters

initial pressure on the gas P1 = 63 atm

standard pressure as P2 = 1 atm

Final volume at standard pressure V2 =?

The data given shows that Boyle's law equation is to used:

P1V1 = P2V2

rearranging the equation to calculate V2,

V2 = [tex]\frac{P1V1}{P2}[/tex]

Putting the values in the equation:

V2 = [tex]\frac{338X63}{1}[/tex]

     = 21294 L

as the pressure on the gas is reduced to 1 atm the volume of the gas increased incredibly to 21294 litres.

Cricetus

At standard pressure, the new volume of the gas will be "21294 liters".

Pressure and Volume

According to the question,

Gas's initial volume, V₁ = 338 liters

Gas's initial pressure, P₁ = 63 atm

Final pressure, P₂ = 1 atm

By using Boyle's law, we get

→ P₁ V₁ = P₂ V₂

or,

The new volume will be:

→ V₂ = [tex]\frac{P_1 V_1}{P_2}[/tex]

By substituting the values,

       = [tex]\frac{338\times 63}{1}[/tex]

       = [tex]\frac{21294}{1}[/tex]

       = 21294 L

Thus the above answer is right.  

Find out more information about Boyle's law here:

https://brainly.com/question/4090112

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