Answer:
3055 years
Explanation:
¹⁴C decays following first-order kinetics. We can find the concentration of ¹⁴C at a certain time using the following expression.
ln [¹⁴C] / [¹⁴C]₀ = - k × t
where,
Given the half-life of ¹⁴C (t1/2 = 5730 years), we can calculate k using the following expression.
k = ln2 / t1/2 = 1.210 × 10⁻⁴ y⁻¹
Then,
ln [¹⁴C] / [¹⁴C]₀ = - k × t
ln 0.691 [¹⁴C]₀ / [¹⁴C]₀ = - 1.210 × 10⁻⁴ y⁻¹ × t
t = 3055 y