Respuesta :
Answer:
a) [tex]\eta_{th} = 10.910\,\%[/tex], b) Yes.
Explanation:
a) The maximum thermal efficiency is given by the Carnot's Cycle, whose formula is:
[tex]\eta_{th} =\left(1-\frac{253.15\,K}{284.15\,K} \right) \times 100\,\%[/tex]
[tex]\eta_{th} = 10.910\,\%[/tex]
b) The claim of the inventor is possible since real efficiency is lower than maximum thermal efficiency.
The maximum thermal efficiency for the given conditions is; η_th = 10.91%
What is the maximum thermal efficiency?
A) The formula for maximum thermal efficiency is;
η_th = [1 - (T_c/T_h)] * 100%
We are given;
Cold temperature;T_c = -20°C = 253.15 K
Hotter temperature; T_h = 11°C = 284.15 K
Thus;
η_th = [1 - (253.15/284.15)] * 100%
η_th = 10.91%
B) We are told that the thermal efficiency is 10% but then we got a maximum thermal efficiency that is higher than the given efficiency. Thus, we conclude that;
The claim of the inventor is possible since real efficiency is lower than maximum thermal efficiency.
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