Answer : The volume of solution is, 0.609 L
Explanation : Given,
Mass of [tex]KH_2AsO_4[/tex] = 6.30 g
Molar mass of [tex]KH_2AsO_4[/tex] = 180 g/mole
Concentration = [tex]5.75\times 10^{-2}M[/tex]
Molarity : It is defined as the number of moles of solute present in one liter of volume of solution.
Formula used :
[tex]\text{Molarity}=\frac{\text{Mass of }KH_2AsO_4}{\text{Molar mass of }KH_2AsO_4\times \text{Volume of solution (in L)}}[/tex]
Now put all the given values in this formula, we get:
[tex]5.75\times 10^{-2}M=\frac{6.30g}{180g/mole\times \text{Volume of solution (in L)}}[/tex]
[tex]\text{Volume of solution (in L)}=0.609L[/tex]
Therefore, the volume of solution is, 0.609 L
