Respuesta :
Answer:
In order to apply the z proportion test we need to verify the following conditions:
1) Randomization we need a random sample.
2) 10 % condition we need that the sample size would be lower than 10% of the population size
3) We need to satisfy the normalyti condition:
n⋅p≥10 and n⋅(1−p)≥10
And for this case we satisfy all the conditions
We need to conduct a hypothesis in order to test the claim that the true proportion is higher than 0.28, so the correct system of hypothesis are:
Null hypothesis:[tex]p \leq 0.28[/tex]
Alternative hypothesis:[tex]p > 0.28[/tex]
Step-by-step explanation:
Data given and notation
n=141 represent the random sample taken
X=43 represent the adults that were infected with Lyme disease
[tex]\hat p=\frac{43}{141}=0.305[/tex] estimated proportion of adults infected with Lyme disease
[tex]p_o=0.28[/tex] is the value that we want to test
[tex]\alpha=[/tex] represent the significance level
z would represent the statistic (variable of interest)
[tex]p_v[/tex] represent the p value (variable of interest)
Solution to the problem
In order to apply the z proportion test we need to verify the following conditions:
1) Randomization we need a random sample.
2) 10 % condition we need that the sample size would be lower than 10% of the population size
3) We need to satisfy the normalyti condition:
n⋅p≥10 and n⋅(1−p)≥10
And for this case we satisfy all the conditions
We need to conduct a hypothesis in order to test the claim that the true proportion is higher than 0.28, so the correct system of hypothesis are:
Null hypothesis:[tex]p \leq 0.28[/tex]
Alternative hypothesis:[tex]p > 0.28[/tex]
