A student enters the lab and conducts Part A of the Experiment. The student uses 25.00 mL of 2.112 M HCl, and adds NaOH in excess as instructed. If the ΔH of the neutralization reaction is known to be -57,320 J/mol H2O, what is the total theoretical heat released (in Joules)?

Respuesta :

Answer:  3026.5 J

Explanation:

To calculate the number of moles for given molarity, we use the equation:

[tex]\text{Molarity of the solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution (in L)}}[/tex]     .....(1)

Molarity of [tex]HCl[/tex] solution = 2.112 M

Volume of solution = 25.00 mL

Putting values in equation 1, we get:

a) [tex]2.112M=\frac{\text{Moles of}HCl\times 1000}{25.00ml}\\\\\text{Moles of }HCl=\frac{2.112mol/L\times 25.00}{1000}=0.05280mol[/tex]

The balanced chemical reaction is:

[tex]HCl+NaOH\rightarrow NaCl+H_2O[/tex]

As [tex]HCl[/tex] is the limiting reagent , it limits the formation of product. [tex]NaOH[/tex] is the excess reagent.

1 mole of HCl produces = 1 mole of [tex]H_2O[/tex]

0.05280 mole of HCl produces = [tex]\frac{1}{1}\times 0.05280=0.05280[/tex] moles of [tex]H_2O[/tex]

Given :

Energy released when 1 mole of [tex]H_2O[/tex] is produced = 57320 J

Thus Energy released when 0.05280 moles of [tex]H_2O[/tex] is produced = [tex]\frac{57320J}{1}\times 0.05280=3026.5J[/tex]

Thus 3026.5 J is the total theoretical heat released