The spectator ions are K⁺ and NO₃⁻, since these ions do not involve in any reaction.
Explanation:
It is given that a bright yellow precipitate will be formed when the given substance reacts with silver nitrate. Silver nitrate reacts with anion iodide (I⁻) to form yellow precipitate.
In the flame test, if we get purple color then the cation must be Potassium (K⁺).
So if we combine the cation and anion we will get the compound as Potassium Iodide (KI).
K⁺ + I⁻ + Ag⁺ + NO₃⁻ → KNO₃ + AgI (s) ↓
Here Silver and Iodide ions combine to form a precipitate and Potassium and nitrate ions are acting as spectator ions, which do not involve in the reaction.
The ionic compound is KI and when it reacts with AgNO₃ the spectator ions are K⁺ and NO₃⁻.
A solution that contains a cation and an anion is subjected to 2 experiments to confirm their identities.
In the flame test, a purple color is observed. The cation that gives purple is the flame test is potassium.
Upon the addition of silver nitrate, a bright yellow precipitate is formed. The precipitate is AgI, so the anion is iodide.
The ionic compound formed by K⁺ and I⁻ is KI.
The molecular equation for the reaction between AgNO₃ and KI is:
AgNO₃(aq) + KI(aq) ⇒ KNO₃(aq) + AgI(s)
The net ionic equation is:
Ag⁺(aq) + I⁻(aq) ⇒ AgI(s)
The spectator ions, those that don't appear in the net ionic equation, are K⁺ and NO₃⁻.
The ionic compound is KI and when it reacts with AgNO₃ the spectator ions are K⁺ and NO₃⁻.
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