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A single loop of current is immersed in an externally applied uniform magnetic field of 3 Tesla oriented in the positive y direction: begin mathsize 12px style B with rightwards arrow on top equals 3 space j with logical and on top end style T. The loop carries a 1/2 amp current, I = 0.5 A. If the lengths of the sides of the loop are 4 m and 2 m, what is the magnitude of the magnetic moment, mu, of the loop?

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mavila18

Answer:

mu=12Tm^2

Explanation:

the magnetic moment mu of a single loop is given by:

[tex]\mu = I A B[/tex]

where I is the current, B is the magnetic field and A is the area of the loop. By replacing we obtain:

[tex]\mu=(0.5A)(4m*2m)(3T)=12Tm^2[/tex]

hope this helps!!

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