Answer:
A. The balanced equation for the reaction between Cu and AgNO3 is given below:
Cu + 2AgNO3 —> Cu(NO3)2 + 2Ag
B. 68.03g
Explanation:
A. Step 1:
The equation for the reaction between Copper (Cu) and silver nitrate AgNO3. This is illustrated below:
Cu + AgNO3 —> Cu(NO3)2 + Ag
A. Step 2:
Balancing the equation.
Cu + AgNO3 —> Cu(NO3)2 + Ag
The above equation can be balanced as follow:
There are 2 atoms of NO3 on the right side and 1 atom on the left. It can be balance by putting 2 in front of AgNO3 as shown below:
Cu + 2AgNO3 —> Cu(NO3)2 + Ag
There are 2 atoms of Ag on the left side and 1 atom on the right. It can be balance by putting 2 in front of Ag as shown below:
Cu + 2AgNO3 —> Cu(NO3)2 + 2Ag
Now the equation is balanced.
B. Step 1:
Determination of the mass Cu that reacted and the mass of Ag produced from the balanced equation. This is shown below:
Cu + 2AgNO3 —> Cu(NO3)2 + 2Ag
Molar Mass of Cu = 63.5g/mol
Molar Mass of Ag = 108g/mol.
Mass of Ag from the balanced equation = 2 x 108 = 216g
From the balanced equation above,
63.5g of Cu reacted.
216g of Ag is produced.
B. Step 2:
Determination of the theoretical yield of Ag.
The theoretical yield of Ag can be obtained as follow:
From the balanced equation above,
63.5g of Cu reacted to produce 216g of Ag.
Therefore, 20g of Cu will react to produce = (20x216)/63.5 = 68.03g of Ag.
Therefore, the theoretical yield of Ag is 68.03g
