A spaceship moves away from the Earth with a speed of 0.80c. Thespaceship then fires a missile with a speed of 0.50c relative to the spaceship.

Part A

What is the velocity of the missile measured by observers on theEarth if the missile is fired toward the Earth?

Part B

What is the velocity of the missile measured by observers on theEarth if the missile is fired away from the Earth?

Respuesta :

Answer:

the velocity of the missile measured by observers on the Earth if the missile is fired toward the Earth = 0.50 c

the velocity of the missile measured by observers on the Earth if the missile is fired away from the Earth = 0.928 c

Explanation:

According to the addition of relativistic velocities;

[tex]v = \frac{v_1+v_2}{1+v_1 * \frac{v_2}{c_2}}[/tex]

Let the velocity toward the earth be negative; then

[tex]v_1 = 0.80c\\\\v_2 = -0.50 c\\\\v = \frac{(0.80*c-0.50*c)}{(1-0.80*0.50*\frac{c^2}{c^2})})\\\\\\v = \frac{0.30c}{0.60}\\ \\v = 0.50 c[/tex]

Let the velocity away from the Earth be positive;

Then:

[tex]v_1 = 0.80 c \\\\v_2 = 0.50 c\\\\v = \frac{0.80c + 0.50 c)}{1+0.80*0.50*\frac{c^2}{c^2}}\\ \\v = \frac{1.30 c}{1.40 c}\\\\v = 0.928 c[/tex]